If the secondary turns Ns are greater than primary turns Np in an ideal transformer, Vs is relative to Vp how?

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Multiple Choice

If the secondary turns Ns are greater than primary turns Np in an ideal transformer, Vs is relative to Vp how?

Explanation:
In an ideal transformer, the voltages scale with the turns ratio: Vs/Vp = Ns/Np. The same magnetic flux links both windings, so the induced EMF is proportional to the number of turns. If the secondary has more turns than the primary, the turns ratio is greater than one, making Vs larger than Vp. So Vs > Vp. (Power balance then gives Is = Ip · (Np/Ns), so the secondary current is smaller when Ns > Np.)

In an ideal transformer, the voltages scale with the turns ratio: Vs/Vp = Ns/Np. The same magnetic flux links both windings, so the induced EMF is proportional to the number of turns. If the secondary has more turns than the primary, the turns ratio is greater than one, making Vs larger than Vp. So Vs > Vp. (Power balance then gives Is = Ip · (Np/Ns), so the secondary current is smaller when Ns > Np.)

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